Re: [cc65] function pointer to __fastcall__ function

From: "Ullrich von Bassewitz"; on Sat, Feb 18, 2012; at 09:20 AM -0500
>
> Greg is right. You need to change the declaration of the pointer:
>
>    void (__fastcall__ *load_func)(uint8_t, char **);

"fastcall" qualifies the function, not the pointer.  So, shouldn't it be
placed outside the parentheses?

   void __fastcall__ (*load_func)(uint8_t, char **);

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