On Saturday 26 September 2009, Maspethrose7@aol.com wrote: > I know how to declare a pointer to an array <char* (*list) [32]> but > how do I allocate and use one? While it is possible to declare it in one step, I would prefer splitting it up with a type definition. Then it is easier to read and you don't have to retype parts of the declaration when getting the size to allocate. ---- #include <stdio.h> #include <stdlib.h> typedef char* A[32]; A *list; int main(void) { list = calloc(1, sizeof(A)); *list[3] = "hello"; puts(*list[3]); free(list); return 0; } ---- Of course a more meaningful name than `A` should be used. Ciao, Marc 'BlackJack' Rintsch -- "Very funny, Scotty. Now beam down my clothes." ---------------------------------------------------------------------- To unsubscribe from the list send mail to majordomo@musoftware.de with the string "unsubscribe cc65" in the body(!) of the mail.
This archive was generated by hypermail 2.1.8 : 2009-09-27 10:57:54 CEST