From: Mike McCarty (jmccarty_at_ssd.usa.alcatel.com)
Date: 2002-03-05 22:08:35
On Tue, 5 Mar 2002, groepaz wrote:
> its implicitly int in this case if my memory serves me right....
The syntax
struct s *p;
declares p to be of type pointer to struct s. At this point we still
don't know the size of an s. It does not default to int. I quote the Standard:
6.2.5 Types
[#1] ... Types are partitioned
into object types (types that describe objects), function
types (types that describe functions), and incomplete types
(types that describe objects but lack information needed to
determine their sizes).
Mike
--
char *p="char *p=%c%s%c;main(){printf(p,34,p,34);}";main(){printf(p,34,p,34);}
This message made from 100% recycled bits.
I can explain it for you, but I can't understand it for you.
I don't speak for Alcatel <- They make me say that.
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