Hi! On Mon, Feb 11, 2008 at 09:48:12AM +0100, Spiro Trikaliotis wrote: > But: i is NOT part of s, it is declared outside: Yes, sorry. I got the code completely wrong. Maybe it was to early for me in the morning:-) A pointer to a local variable is not considered constant, because code must be generated to calculate it. Since local structs get initialized by the compiler generating a template in read only data, it is necessary that data placed there can be evaluated at compile time. I'm not sure how much work it is to change that. Regards Uz -- Ullrich von Bassewitz uz@musoftware.de ---------------------------------------------------------------------- To unsubscribe from the list send mail to majordomo@musoftware.de with the string "unsubscribe cc65" in the body(!) of the mail.Received on Mon Feb 11 09:56:21 2008
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